>> db.car.distinct('name')
[ "honda", "tat", "tata", "tata3" ]
>> db.car.find({"name":/. *ta.* /})
↧
Answer by arnav for How to query MongoDB with "like"?
↧
Channel:
How to query MongoDB with "like" - Stack Overflow
X
Are you the publisher?
Claim or
contact us
about this channel.
X
No ratings yet.
Channel Details:
- Title: How to query MongoDB with "like" - Stack Overflow
- Channel Number: 75705827
- Language: English
- Registered On: November 1, 2019, 6:27 am
- Number of Articles: 48
- Latest Snapshot: October 2, 2023, 1:17 pm
- RSS URL: https://stackoverflow.com/feeds/question/3305561
- Publisher: https://stackoverflow.com/q/3305561
- Description:
- Catalog: //mongodb464.rssing.com/catalog.php?indx=75705827
© 2025 //www.rssing.com